Problem of the Week Update 3
Congratulations to this week's winners: Jobert Gimeno - 3rd Year ECE of PUP Sta. Mesa, Cielito Matienzo - 1st Year ECE of PUP Taguig Campus and Lord Alfred Remorin - 4th Year ECE of PUP Sta. Mesa. All the winning solutions gave the following arrangement of answer.
Solution by Jober Gimeno:
posted by zarcsman at
7:24 PM
1 Comments:
Given cos36=(1+(5)^½)/4
cos30=(3)^½/2
Find cos3
cos(36-30)=cos36cos30+sin36sin30
=[(1+(5)^½)/4][(3)^½/2]+[(1²-[(1+(5)½)/4]²]^½[1/2]
={[(3)^½+(15)^½]/8}+
{[10-2(5)^½]^½}/8
cos6={(3)^½+(15)^½+[10-2(5)^½]^½}/8
Using Half Angle Formula:
cos½(6)={[1+cos6]/2}^½
={[1+{1+{(3)^½+(15)^½+[10-2(5)^½]^½}/8]/2}^½
={8+(3)^½+(15)^½+[10-2(5)^½]^½}^½/4
Ang gulo nang sag0t q. . .
nauna aq jan sa lahat ng nagpost..
alam q n ung sag0t saturday night pa lamang. .
ala lang aq time mag internet. .
By
Anonymous, at 8:24 PM
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